How to calculate permutations12/11/2023 ![]() ![]() The macro will work for any number of items in the A column, within Excel limits. If (UBound(vresult) = UBound(unique)) ThenĬall PermutationsNPR(vElements, p, vresult, lRow, iIndex + 1)įunction UniqueArray(todoarray As Variant) As Variant Sub PermutationsNPR(vElements As Variant, p As Long, vresult As Variant, lRow As Long, iIndex As Integer) VElements = Application.Transpose(Range("A1", Range("A1").End(xlDown)))Ĭall PermutationsNPR(vElements, i, vresult, lRow, 1) The following VBA script created for me this spreadsheet:ĭim vElements As Variant, vresult As Variant ![]() It doesn't give me all possible combinations permutations, it just changes what I typed in vertically down a column, and outputs the results horizontally. In column B the VBA gives me (in a single cell): one,two,three In column A, if I type (one word per row): One I have given this a try but it does not seem to work. So we have the product of two 2 2 -cycles, and. I would like to be able to type in any number of input values and the input values will be any word, phrase, number, letters, or a combination permutation of all of those. (123)(241) (13)(24) ( 123) ( 241) ( 13) ( 24) Second, the order of a one-cycle permutation is its length to find the order of a product of more than one permutation cycle, as is the case here, the order of is the lcm lcm of the lengths of the cycles. Here is what it should look like if 3 values are given:ĭoes anyone know how to do this in Excel? The output generated should be something like this One How do I go about creating a formula which takes any number of given input values, and then generates an output value with all possible combinations permutations based on the input values given.įor example, if the input values where as following One Permutation Calculator The permutation is the process to compute the elements of a set into the subset where the arrangement of the elements is important. Edit: Okay, not sure if my way is faster than the solution posted by Andreas (factoring as a product of cycles), I guess both are useful to know. Therefore, the suggested duplicate does not answer my question. The fastest way (without using tools such as Lagrange's theorem) is to calculate by repeated squaring: A9 (((A2)2)2)A A 9 ( ( ( A 2) 2) 2) A. The suggested duplicate always shows column A at the left most position of the output, column b in the middle of the output and column c at the left of the output. In this equation, n represents the number of items to choose from and r represents how many items are being. The suggested duplicate always provides 3 inputs per variation.įurthermore, my question also asks for variations to show all possible orders of the inputs too. To calculate a permutation, you will need to use the formula n P r n / ( n - r ). The suggested duplicate does not show all possible variations based on the number of options, so an input of 3 can have a variation of 1, 2, and 3 of the inputs. Please note my question is different from the suggested duplicate. ![]()
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